Home Physics Wave Optics JEE (Advanced) / IIT - JEE Problems ( Previous Years ) Using the expression 2d sin θ = λ , one calc…
Physics Wave Optics JEE (Advanced) / IIT - JEE Problems ( Previous Years ) MCQ (Single Correct)

Using the expression 2d sin θ = λ , one calculates the values of d by measuring the corresponding angles θ in the range 0 to 90º. The wavelength λ is exactly knowns and the error in θ is constant for all values of θ . As θ increases from 0º :

A
the absolute error in d remains constant.
B
the absolute error in d increases.
C
the fractional error in d remains constant.
D
the fractional error in d decreases

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The correct answer is:
D

Sol. 2d sin θ = λ

d =

differntiate

∂ = (cosec θ )

∂ =

∂ =

as θ = increases , decreases

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